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3.14(4x)^2=23.07
We move all terms to the left:
3.14(4x)^2-(23.07)=0
We add all the numbers together, and all the variables
3.144x^2-23.07=0
a = 3.144; b = 0; c = -23.07;
Δ = b2-4ac
Δ = 02-4·3.144·(-23.07)
Δ = 290.12832
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{290.12832}}{2*3.144}=\frac{0-\sqrt{290.12832}}{6.288} =-\frac{\sqrt{}}{6.288} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{290.12832}}{2*3.144}=\frac{0+\sqrt{290.12832}}{6.288} =\frac{\sqrt{}}{6.288} $
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